What are the solutions to the equation x^2+0x-4=0 ?

The solutions to the equation x^2+0x-4=0 are x=2,x=-2

Find the zeros of x^2+0x-4=0

The zeros of x^2+0x-4=0 are x=2,x=-2

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x^{2} + 0 x - 4 = 0

x = 2, x = - 2

Solution steps

x^{2} + 0 \cdot x - 4 = 0

Refine

x^{2} - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

0^{2} - 4 \cdot 1 \cdot (- 4) = 4

x_{1, 2} = \frac{- 0 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 0 + 4}{2 \cdot 1}, x_{2} = \frac{- 0 - 4}{2 \cdot 1}

x = \frac{- 0 + 4}{2 \cdot 1} : 2

x = \frac{- 0 - 4}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 2, x = - 2

n^{2} - 4 n = 11

x^{2} - 7 x - 34 = 0

x^{2} + 289 = 0

9 x^{2} + 7 x - 56 = 0

5 n^{2} + 19 n + 12 = 0

What are the solutions to the equation x^2+0x-4=0 ?
The solutions to the equation x^2+0x-4=0 are x=2,x=-2
Find the zeros of x^2+0x-4=0
The zeros of x^2+0x-4=0 are x=2,x=-2