What are the solutions to the equation x^2+4^2=6^2 ?

The solutions to the equation x^2+4^2=6^2 are x=2sqrt(5),x=-2sqrt(5)

Find the zeros of x^2+4^2=6^2

The zeros of x^2+4^2=6^2 are x=2sqrt(5),x=-2sqrt(5)

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x^{2} + 4^{2} = 6^{2}

x = 25, x = - 25

Decimal Notation

x = 4.47213 \dots, x = - 4.47213 \dots

Solution steps

x^{2} + 4^{2} = 6^{2}

Move

4^{2}

to the right side

x^{2} = 20

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 20, x = - 20

20 = 25

- 20 = - 25

x = 25, x = - 25

32 x^{2} - 6 x + 9 = 0

x^{2} - 3 x - 1

z^{2} - 12 z + 35 = 0

2 x (2 x + 1) = 5

x^{2} + \frac{3}{3} x + \frac{1}{3} = 0

What are the solutions to the equation x^2+4^2=6^2 ?
The solutions to the equation x^2+4^2=6^2 are x=2sqrt(5),x=-2sqrt(5)
Find the zeros of x^2+4^2=6^2
The zeros of x^2+4^2=6^2 are x=2sqrt(5),x=-2sqrt(5)