What are the solutions to the equation 25x^2+10x+25=0 ?

The solutions to the equation 25x^2+10x+25=0 are x=-1/5+i(2sqrt(6))/5 ,x=-1/5-i(2sqrt(6))/5

Find the zeros of 25x^2+10x+25=0

The zeros of 25x^2+10x+25=0 are x=-1/5+i(2sqrt(6))/5 ,x=-1/5-i(2sqrt(6))/5

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25 x^{2} + 10 x + 25 = 0

x = - \frac{1}{5} + i \frac{2 6}{5}, x = - \frac{1}{5} - i \frac{2 6}{5}

Solution steps

25 x^{2} + 10 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 25 \cdot 25}{2 \cdot 25}

Simplify

1 0^{2} - 4 \cdot 25 \cdot 25 : 206 i

x_{1, 2} = \frac{- 10 \pm 20 6 i}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- 10 + 20 6 i}{2 \cdot 25}, x_{2} = \frac{- 10 - 20 6 i}{2 \cdot 25}

x = \frac{- 10 + 20 6 i}{2 \cdot 25} : - \frac{1}{5} + i \frac{2 6}{5}

x = \frac{- 10 - 20 6 i}{2 \cdot 25} : - \frac{1}{5} - i \frac{2 6}{5}

The solutions to the quadratic equation are:

x = - \frac{1}{5} + i \frac{2 6}{5}, x = - \frac{1}{5} - i \frac{2 6}{5}

4 s^{2} - 81 = 0

6 x^{2} - 48 x = 0

- 16 t^{2} + 48 t + 160 = 160

r (r + 4) = 0

2 (x^{2} - 2 x) = 5

What are the solutions to the equation 25x^2+10x+25=0 ?
The solutions to the equation 25x^2+10x+25=0 are x=-1/5+i(2sqrt(6))/5 ,x=-1/5-i(2sqrt(6))/5
Find the zeros of 25x^2+10x+25=0
The zeros of 25x^2+10x+25=0 are x=-1/5+i(2sqrt(6))/5 ,x=-1/5-i(2sqrt(6))/5