What are the solutions to the equation v^2+10v+24=0 ?

The solutions to the equation v^2+10v+24=0 are v=-4,v=-6

Find the zeros of v^2+10v+24=0

The zeros of v^2+10v+24=0 are v=-4,v=-6

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v^{2} + 10 v + 24 = 0

v = - 4, v = - 6

Solution steps

v^{2} + 10 v + 24 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 24 = 2

v_{1, 2} = \frac{- 10 \pm 2}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 10 + 2}{2 \cdot 1}, v_{2} = \frac{- 10 - 2}{2 \cdot 1}

v = \frac{- 10 + 2}{2 \cdot 1} : - 4

v = \frac{- 10 - 2}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

v = - 4, v = - 6

(2.629 - x) (0.458 - x) - 0.80 1^{2} = 0

3 p^{2} = - 8 p - 3

8 - 6 m^{2} = - 88

0 = x^{2} - x

z^{2} + 7 z + 10 = 0

What are the solutions to the equation v^2+10v+24=0 ?
The solutions to the equation v^2+10v+24=0 are v=-4,v=-6
Find the zeros of v^2+10v+24=0
The zeros of v^2+10v+24=0 are v=-4,v=-6