What are the solutions to the equation 0=x^2-x ?

The solutions to the equation 0=x^2-x are x=1,x=0

Find the zeros of 0=x^2-x

The zeros of 0=x^2-x are x=1,x=0

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0 = x^{2} - x

x = 1, x = 0

Solution steps

0 = x^{2} - x

Switch sides

x^{2} - x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot 0 = 1

x_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 1}

x = \frac{- ( - 1 ) + 1}{2 \cdot 1} : 1

x = \frac{- ( - 1 ) - 1}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 1, x = 0

x^{2} + 2 x - 35 = 0

z^{2} + 7 z + 10 = 0

r^{2} - 18 = 7 r

s^{2} - 2 s + 4

\frac{2 x ^{2}}{9} - \frac{1}{50} = 0

What are the solutions to the equation 0=x^2-x ?
The solutions to the equation 0=x^2-x are x=1,x=0
Find the zeros of 0=x^2-x
The zeros of 0=x^2-x are x=1,x=0