What are the solutions to the equation r^2-18=7r ?

The solutions to the equation r^2-18=7r are r=9,r=-2

Find the zeros of r^2-18=7r

The zeros of r^2-18=7r are r=9,r=-2

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r^{2} - 18 = 7 r

r = 9, r = - 2

Solution steps

r^{2} - 18 = 7 r

Move

7 r

to the left side

r^{2} - 18 - 7 r = 0

Write in the standard form

a x^{2} + b x + c = 0

r^{2} - 7 r - 18 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 18) = 11

r_{1, 2} = \frac{- ( - 7 ) \pm 11}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 7 ) + 11}{2 \cdot 1}, r_{2} = \frac{- ( - 7 ) - 11}{2 \cdot 1}

r = \frac{- ( - 7 ) + 11}{2 \cdot 1} : 9

r = \frac{- ( - 7 ) - 11}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

r = 9, r = - 2

s^{2} - 2 s + 4

\frac{2 x ^{2}}{9} - \frac{1}{50} = 0

x, x^{2} y^{1} = 4 x^{2} + 7 x y + 2 y^{2}

1 0^{2} + 4^{2} = c^{2}

x^{2} = - 5 x + 8

What are the solutions to the equation r^2-18=7r ?
The solutions to the equation r^2-18=7r are r=9,r=-2
Find the zeros of r^2-18=7r
The zeros of r^2-18=7r are r=9,r=-2