What are the solutions to the equation 10^2+4^2=c^2 ?

The solutions to the equation 10^2+4^2=c^2 are c=2sqrt(29),c=-2sqrt(29)

Find the zeros of 10^2+4^2=c^2

The zeros of 10^2+4^2=c^2 are c=2sqrt(29),c=-2sqrt(29)

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1 0^{2} + 4^{2} = c^{2}

c = 229, c = - 229

Decimal Notation

c = 10.77032 \dots, c = - 10.77032 \dots

Solution steps

1 0^{2} + 4^{2} = c^{2}

Switch sides

c^{2} = 1 0^{2} + 4^{2}

Simplify

1 0^{2} + 4^{2} : 116

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 116, c = - 116

116 = 229

- 116 = - 229

c = 229, c = - 229

x^{2} = - 5 x + 8

4 x^{2} - 32 x + 48 = 0

- 3 x^{2} + 18 x + 120 = 0

x^{2} - 2 x - 24 = 0

6 a^{2} - 9 a = 0

What are the solutions to the equation 10^2+4^2=c^2 ?
The solutions to the equation 10^2+4^2=c^2 are c=2sqrt(29),c=-2sqrt(29)
Find the zeros of 10^2+4^2=c^2
The zeros of 10^2+4^2=c^2 are c=2sqrt(29),c=-2sqrt(29)