What are the solutions to the equation -3x^2+18x+120=0 ?

The solutions to the equation -3x^2+18x+120=0 are x=-4,x=10

Find the zeros of -3x^2+18x+120=0

The zeros of -3x^2+18x+120=0 are x=-4,x=10

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- 3 x^{2} + 18 x + 120 = 0

x = - 4, x = 10

Solution steps

- 3 x^{2} + 18 x + 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 ( - 3 ) \cdot 120}{2 ( - 3 )}

1 8^{2} - 4 (- 3) \cdot 120 = 42

x_{1, 2} = \frac{- 18 \pm 42}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 18 + 42}{2 ( - 3 )}, x_{2} = \frac{- 18 - 42}{2 ( - 3 )}

x = \frac{- 18 + 42}{2 ( - 3 )} : - 4

x = \frac{- 18 - 42}{2 ( - 3 )} : 10

The solutions to the quadratic equation are:

x = - 4, x = 10

x^{2} - 2 x - 24 = 0

6 a^{2} - 9 a = 0

2 x^{2} - 14 x - 60 = 0

\frac{1}{2} x^{2} + 1 = 0

2^{2} + 1. 5^{2} = x^{2}

What are the solutions to the equation -3x^2+18x+120=0 ?
The solutions to the equation -3x^2+18x+120=0 are x=-4,x=10
Find the zeros of -3x^2+18x+120=0
The zeros of -3x^2+18x+120=0 are x=-4,x=10