What are the solutions to the equation 2^2+1.5^2=x^2 ?

The solutions to the equation 2^2+1.5^2=x^2 are x= 5/2 ,x=-5/2

Find the zeros of 2^2+1.5^2=x^2

The zeros of 2^2+1.5^2=x^2 are x= 5/2 ,x=-5/2

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2^{2} + 1. 5^{2} = x^{2}

x = \frac{5}{2}, x = - \frac{5}{2}

Solution steps

2^{2} + 1. 5^{2} = x^{2}

Switch sides

x^{2} = 2^{2} + 1. 5^{2}

Simplify

2^{2} + 1. 5^{2} : 6.25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 6.25, x = - 6.25

6.25 = \frac{5}{2}

- 6.25 = - \frac{5}{2}

x = \frac{5}{2}, x = - \frac{5}{2}

(x + 2) 2 + 3 (x + 1) (x + 4) = (x - 3) (x + 3) - 1

2 (x + 5)^{2} = 8

9 x^{2} - 16 x - 7 = 2 x + 9

72 x^{2} - 48 x = 0

4 x^{2} + 2 = 10

What are the solutions to the equation 2^2+1.5^2=x^2 ?
The solutions to the equation 2^2+1.5^2=x^2 are x= 5/2 ,x=-5/2
Find the zeros of 2^2+1.5^2=x^2
The zeros of 2^2+1.5^2=x^2 are x= 5/2 ,x=-5/2