What are the solutions to the equation x^2+1.2x+0.56=0.91 ?

The solutions to the equation x^2+1.2x+0.56=0.91 are x=(-6+sqrt(71))/(10),x=-(6+sqrt(71))/(10)

Find the zeros of x^2+1.2x+0.56=0.91

The zeros of x^2+1.2x+0.56=0.91 are x=(-6+sqrt(71))/(10),x=-(6+sqrt(71))/(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 1.2 x + 0.56 = 0.91

x = \frac{- 6 + 71}{10}, x = - \frac{6 + 71}{10}

Decimal Notation

x = 0.24261 \dots, x = - 1.44261 \dots

Solution steps

x^{2} + 1.2 x + 0.56 = 0.91

Multiply both sides by

100

100 x^{2} + 120 x + 56 = 91

Move

91

to the left side

100 x^{2} + 120 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 120 \pm 12 0 ^{2} - 4 \cdot 100 ( - 35 )}{2 \cdot 100}

12 0^{2} - 4 \cdot 100 (- 35) = 2071

x_{1, 2} = \frac{- 120 \pm 20 71}{2 \cdot 100}

Separate the solutions

x_{1} = \frac{- 120 + 20 71}{2 \cdot 100}, x_{2} = \frac{- 120 - 20 71}{2 \cdot 100}

x = \frac{- 120 + 20 71}{2 \cdot 100} : \frac{- 6 + 71}{10}

x = \frac{- 120 - 20 71}{2 \cdot 100} : - \frac{6 + 71}{10}

The solutions to the quadratic equation are:

x = \frac{- 6 + 71}{10}, x = - \frac{6 + 71}{10}

6 y^{2} - 19 y + 8 = 0

x = - x^{2} + 2 x + 3

12 x^{2} + 18 x + 6 = 0

(8 x - 10) (x - 1) = 0

x^{2} + 56 x = 8.16

What are the solutions to the equation x^2+1.2x+0.56=0.91 ?
The solutions to the equation x^2+1.2x+0.56=0.91 are x=(-6+sqrt(71))/(10),x=-(6+sqrt(71))/(10)
Find the zeros of x^2+1.2x+0.56=0.91
The zeros of x^2+1.2x+0.56=0.91 are x=(-6+sqrt(71))/(10),x=-(6+sqrt(71))/(10)