What are the solutions to the equation (8x-10)(x-1)=0 ?

The solutions to the equation (8x-10)(x-1)=0 are x= 5/4 ,x=1

Find the zeros of (8x-10)(x-1)=0

The zeros of (8x-10)(x-1)=0 are x= 5/4 ,x=1

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(8 x - 10) (x - 1) = 0

x = \frac{5}{4}, x = 1

Solution steps

(8 x - 10) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

8 x - 10 = 0 or x - 1 = 0

Solve

8 x - 10 = 0 : x = \frac{5}{4}

Solve

x - 1 = 0 : x = 1

The solutions to the quadratic equation are:

x = \frac{5}{4}, x = 1

x^{2} + 56 x = 8.16

x, 2 x^{2} + 7 x + 5 = 0

x (4 x - 1) = 5

u, A = 28 u^{2}

n^{2} + 8 = 80

What are the solutions to the equation (8x-10)(x-1)=0 ?
The solutions to the equation (8x-10)(x-1)=0 are x= 5/4 ,x=1
Find the zeros of (8x-10)(x-1)=0
The zeros of (8x-10)(x-1)=0 are x= 5/4 ,x=1