What are the solutions to the equation x(4x-1)=5 ?

The solutions to the equation x(4x-1)=5 are x= 5/4 ,x=-1

Find the zeros of x(4x-1)=5

The zeros of x(4x-1)=5 are x= 5/4 ,x=-1

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x (4 x - 1) = 5

x = \frac{5}{4}, x = - 1

Solution steps

x (4 x - 1) = 5

Expand

x (4 x - 1) : 4 x^{2} - x

4 x^{2} - x = 5

Move

5

to the left side

4 x^{2} - x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 4 ( - 5 )}{2 \cdot 4}

(- 1)^{2} - 4 \cdot 4 (- 5) = 9

x_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 9}{2 \cdot 4}, x_{2} = \frac{- ( - 1 ) - 9}{2 \cdot 4}

x = \frac{- ( - 1 ) + 9}{2 \cdot 4} : \frac{5}{4}

x = \frac{- ( - 1 ) - 9}{2 \cdot 4} : - 1

The solutions to the quadratic equation are:

x = \frac{5}{4}, x = - 1

u, A = 28 u^{2}

n^{2} + 8 = 80

2 x^{2} - 61 = 139

a^{2} - 64 = 0

- 4 x^{2} + 24 x

What are the solutions to the equation x(4x-1)=5 ?
The solutions to the equation x(4x-1)=5 are x= 5/4 ,x=-1
Find the zeros of x(4x-1)=5
The zeros of x(4x-1)=5 are x= 5/4 ,x=-1