What are the solutions to the equation solvefor u,A=28u^2 ?

The solutions to the equation solvefor u,A=28u^2 are u=(sqrt(A))/(2sqrt(7)),u=-(sqrt(A))/(2sqrt(7))

Find the zeros of solvefor u,A=28u^2

The zeros of solvefor u,A=28u^2 are u=(sqrt(A))/(2sqrt(7)),u=-(sqrt(A))/(2sqrt(7))

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solve for

u, A = 28 u^{2}

u = \frac{A}{2 7}, u = - \frac{A}{2 7}

Solution steps

A = 28 u^{2}

Switch sides

28 u^{2} = A

Divide both sides by

28

u^{2} = \frac{A}{28}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

u = \frac{A}{28}, u = - \frac{A}{28}

Simplify

\frac{A}{28} : \frac{A}{2 7}

Simplify

- \frac{A}{28} : - \frac{A}{2 7}

u = \frac{A}{2 7}, u = - \frac{A}{2 7}

n^{2} + 8 = 80

2 x^{2} - 61 = 139

a^{2} - 64 = 0

- 4 x^{2} + 24 x

- 8 + 81 x^{2} = 56

What are the solutions to the equation solvefor u,A=28u^2 ?
The solutions to the equation solvefor u,A=28u^2 are u=(sqrt(A))/(2sqrt(7)),u=-(sqrt(A))/(2sqrt(7))
Find the zeros of solvefor u,A=28u^2
The zeros of solvefor u,A=28u^2 are u=(sqrt(A))/(2sqrt(7)),u=-(sqrt(A))/(2sqrt(7))