What are the solutions to the equation -8+81x^2=56 ?

The solutions to the equation -8+81x^2=56 are x= 8/9 ,x=-8/9

Find the zeros of -8+81x^2=56

The zeros of -8+81x^2=56 are x= 8/9 ,x=-8/9

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- 8 + 81 x^{2} = 56

x = \frac{8}{9}, x = - \frac{8}{9}

Solution steps

- 8 + 81 x^{2} = 56

Move

8

to the right side

81 x^{2} = 64

Divide both sides by

81

x^{2} = \frac{64}{81}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{64}{81}, x = - \frac{64}{81}

\frac{64}{81} = \frac{8}{9}

- \frac{64}{81} = - \frac{8}{9}

x = \frac{8}{9}, x = - \frac{8}{9}

3 x^{2} - 2 x + 1 = 4

x^{2} - 18 x + 16 = 0

x, x^{2} - 8 x + 16 = 0

(x - 4)^{2} + (x - 1) \cdot (x + 1) = 25

x^{2} + 3 = - 24

What are the solutions to the equation -8+81x^2=56 ?
The solutions to the equation -8+81x^2=56 are x= 8/9 ,x=-8/9
Find the zeros of -8+81x^2=56
The zeros of -8+81x^2=56 are x= 8/9 ,x=-8/9