What are the solutions to the equation -x^2+5x+7=0 ?

The solutions to the equation -x^2+5x+7=0 are x=-(-5+sqrt(53))/2 ,x=(5+sqrt(53))/2

Find the zeros of -x^2+5x+7=0

The zeros of -x^2+5x+7=0 are x=-(-5+sqrt(53))/2 ,x=(5+sqrt(53))/2

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- x^{2} + 5 x + 7 = 0

x = - \frac{- 5 + 53}{2}, x = \frac{5 + 53}{2}

Decimal Notation

x = - 1.14005 \dots, x = 6.14005 \dots

Solution steps

- x^{2} + 5 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 1 ) \cdot 7}{2 ( - 1 )}

5^{2} - 4 (- 1) \cdot 7 = 53

x_{1, 2} = \frac{- 5 \pm 53}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 5 + 53}{2 ( - 1 )}, x_{2} = \frac{- 5 - 53}{2 ( - 1 )}

x = \frac{- 5 + 53}{2 ( - 1 )} : - \frac{- 5 + 53}{2}

x = \frac{- 5 - 53}{2 ( - 1 )} : \frac{5 + 53}{2}

The solutions to the quadratic equation are:

x = - \frac{- 5 + 53}{2}, x = \frac{5 + 53}{2}

3 x^{2} - 5 = - 14 x

3 x^{2} + 5 x - 2 = 0

x^{2} + 32 = - 14 x

y, \frac{x ^{3}}{3} + \frac{y ^{2}}{2} - 3 x + 2 y = - \frac{1}{6}

- 3 x^{2} - 6 x - 6 = 0

What are the solutions to the equation -x^2+5x+7=0 ?
The solutions to the equation -x^2+5x+7=0 are x=-(-5+sqrt(53))/2 ,x=(5+sqrt(53))/2
Find the zeros of -x^2+5x+7=0
The zeros of -x^2+5x+7=0 are x=-(-5+sqrt(53))/2 ,x=(5+sqrt(53))/2