What are the solutions to the equation x^2+32=-14x ?

The solutions to the equation x^2+32=-14x are x=-7+sqrt(17),x=-7-sqrt(17)

Find the zeros of x^2+32=-14x

The zeros of x^2+32=-14x are x=-7+sqrt(17),x=-7-sqrt(17)

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x^{2} + 32 = - 14 x

x = - 7 + 17, x = - 7 - 17

Solution steps

x^{2} + 32 = - 14 x

Move

14 x

to the left side

x^{2} + 32 + 14 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 14 x + 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 32}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 32 = 217

x_{1, 2} = \frac{- 14 \pm 2 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 2 17}{2 \cdot 1}, x_{2} = \frac{- 14 - 2 17}{2 \cdot 1}

x = \frac{- 14 + 2 17}{2 \cdot 1} : - 7 + 17

x = \frac{- 14 - 2 17}{2 \cdot 1} : - 7 - 17

The solutions to the quadratic equation are:

x = - 7 + 17, x = - 7 - 17

y, \frac{x ^{3}}{3} + \frac{y ^{2}}{2} - 3 x + 2 y = - \frac{1}{6}

- 3 x^{2} - 6 x - 6 = 0

4 x^{2} - 8 x - 4 = 0

x^{2} + 4 x + 85 = 0

x^{2} - 6 x = - x^{2} + 6 x

What are the solutions to the equation x^2+32=-14x ?
The solutions to the equation x^2+32=-14x are x=-7+sqrt(17),x=-7-sqrt(17)
Find the zeros of x^2+32=-14x
The zeros of x^2+32=-14x are x=-7+sqrt(17),x=-7-sqrt(17)