What are the solutions to the equation x^2-6x=-x^2+6x ?

The solutions to the equation x^2-6x=-x^2+6x are x=6,x=0

Find the zeros of x^2-6x=-x^2+6x

The zeros of x^2-6x=-x^2+6x are x=6,x=0

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x^{2} - 6 x = - x^{2} + 6 x

x = 6, x = 0

Solution steps

x^{2} - 6 x = - x^{2} + 6 x

Move

6 x

to the left side

x^{2} - 12 x = - x^{2}

Move

x^{2}

to the left side

2 x^{2} - 12 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 12)^{2} - 4 \cdot 2 \cdot 0 = 12

x_{1, 2} = \frac{- ( - 12 ) \pm 12}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 12}{2 \cdot 2}, x_{2} = \frac{- ( - 12 ) - 12}{2 \cdot 2}

x = \frac{- ( - 12 ) + 12}{2 \cdot 2} : 6

x = \frac{- ( - 12 ) - 12}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = 6, x = 0

a, 9 a^{2} + 12 ab = 32 b^{2}

c^{2} = 15

x^{2} - \frac{2}{3} = 0

4 x^{2} + 60 x + 200 - 264 = 0

5 x^{2} + 6 x - 15 = 0

What are the solutions to the equation x^2-6x=-x^2+6x ?
The solutions to the equation x^2-6x=-x^2+6x are x=6,x=0
Find the zeros of x^2-6x=-x^2+6x
The zeros of x^2-6x=-x^2+6x are x=6,x=0