What are the solutions to the equation 4x^2+60x+200-264=0 ?

The solutions to the equation 4x^2+60x+200-264=0 are x=1,x=-16

Find the zeros of 4x^2+60x+200-264=0

The zeros of 4x^2+60x+200-264=0 are x=1,x=-16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 60 x + 200 - 264 = 0

x = 1, x = - 16

Solution steps

4 x^{2} + 60 x + 200 - 264 = 0

Refine

4 x^{2} + 60 x - 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 60 \pm 6 0 ^{2} - 4 \cdot 4 ( - 64 )}{2 \cdot 4}

6 0^{2} - 4 \cdot 4 (- 64) = 68

x_{1, 2} = \frac{- 60 \pm 68}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 60 + 68}{2 \cdot 4}, x_{2} = \frac{- 60 - 68}{2 \cdot 4}

x = \frac{- 60 + 68}{2 \cdot 4} : 1

x = \frac{- 60 - 68}{2 \cdot 4} : - 16

The solutions to the quadratic equation are:

x = 1, x = - 16

5 x^{2} + 6 x - 15 = 0

3 x^{2} + 8 x + 9 = 0

6 x^{2} + 3 x + 4 = 0

\frac{1}{7} x^{2} - \frac{3}{7} x = 0

(m + 1)^{2} = 0

What are the solutions to the equation 4x^2+60x+200-264=0 ?
The solutions to the equation 4x^2+60x+200-264=0 are x=1,x=-16
Find the zeros of 4x^2+60x+200-264=0
The zeros of 4x^2+60x+200-264=0 are x=1,x=-16