What are the solutions to the equation 3x^2+8x+9=0 ?

The solutions to the equation 3x^2+8x+9=0 are x=-4/3+i(sqrt(11))/3 ,x=-4/3-i(sqrt(11))/3

Find the zeros of 3x^2+8x+9=0

The zeros of 3x^2+8x+9=0 are x=-4/3+i(sqrt(11))/3 ,x=-4/3-i(sqrt(11))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} + 8 x + 9 = 0

x = - \frac{4}{3} + i \frac{11}{3}, x = - \frac{4}{3} - i \frac{11}{3}

Solution steps

3 x^{2} + 8 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 \cdot 9}{2 \cdot 3}

Simplify

8^{2} - 4 \cdot 3 \cdot 9 : 211 i

x_{1, 2} = \frac{- 8 \pm 2 11 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 8 + 2 11 i}{2 \cdot 3}, x_{2} = \frac{- 8 - 2 11 i}{2 \cdot 3}

x = \frac{- 8 + 2 11 i}{2 \cdot 3} : - \frac{4}{3} + i \frac{11}{3}

x = \frac{- 8 - 2 11 i}{2 \cdot 3} : - \frac{4}{3} - i \frac{11}{3}

The solutions to the quadratic equation are:

x = - \frac{4}{3} + i \frac{11}{3}, x = - \frac{4}{3} - i \frac{11}{3}

6 x^{2} + 3 x + 4 = 0

\frac{1}{7} x^{2} - \frac{3}{7} x = 0

(m + 1)^{2} = 0

x^{2} = 10 x + 24

3 x^{2} + 2 x = - 4

What are the solutions to the equation 3x^2+8x+9=0 ?
The solutions to the equation 3x^2+8x+9=0 are x=-4/3+i(sqrt(11))/3 ,x=-4/3-i(sqrt(11))/3
Find the zeros of 3x^2+8x+9=0
The zeros of 3x^2+8x+9=0 are x=-4/3+i(sqrt(11))/3 ,x=-4/3-i(sqrt(11))/3