What are the solutions to the equation 12x=x^2 ?

The solutions to the equation 12x=x^2 are x=12,x=0

Find the zeros of 12x=x^2

The zeros of 12x=x^2 are x=12,x=0

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12 x = x^{2}

x = 12, x = 0

Solution steps

12 x = x^{2}

Switch sides

x^{2} = 12 x

Move

12 x

to the left side

x^{2} - 12 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 0 = 12

x_{1, 2} = \frac{- ( - 12 ) \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 12}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 12}{2 \cdot 1}

x = \frac{- ( - 12 ) + 12}{2 \cdot 1} : 12

x = \frac{- ( - 12 ) - 12}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 12, x = 0

- 6 x^{2} + 7 x + 3 = 0

(k - 2) x^{2} - (2 k - 1) x + (k - 1) = 0

3 x^{2} - 12 x + 24 = 0

x^{2} - 6 x - 1

- \frac{1}{3} x^{2} + \frac{4}{3} x - \frac{4}{3} = - \frac{1}{6} x^{2} + \frac{2}{3} x - \frac{13}{6}

What are the solutions to the equation 12x=x^2 ?
The solutions to the equation 12x=x^2 are x=12,x=0
Find the zeros of 12x=x^2
The zeros of 12x=x^2 are x=12,x=0