What are the solutions to the equation 13n^2-7=-6-3n^2 ?

The solutions to the equation 13n^2-7=-6-3n^2 are n= 1/4 ,n=-1/4

Find the zeros of 13n^2-7=-6-3n^2

The zeros of 13n^2-7=-6-3n^2 are n= 1/4 ,n=-1/4

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13 n^{2} - 7 = - 6 - 3 n^{2}

n = \frac{1}{4}, n = - \frac{1}{4}

Solution steps

13 n^{2} - 7 = - 6 - 3 n^{2}

Move

7

to the right side

13 n^{2} = - 3 n^{2} + 1

Move

3 n^{2}

to the left side

16 n^{2} = 1

Divide both sides by

16

n^{2} = \frac{1}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = \frac{1}{16}, n = - \frac{1}{16}

\frac{1}{16} = \frac{1}{4}

- \frac{1}{16} = - \frac{1}{4}

n = \frac{1}{4}, n = - \frac{1}{4}

y^{2} - 24 = 0

3 x^{2} - 186 x + 450 = 90

9 x^{2} - 14 x - 8 = 0

6 n^{2} + 9 n + 1 = 0

x^{2} + 15 x + 2 = 0

What are the solutions to the equation 13n^2-7=-6-3n^2 ?
The solutions to the equation 13n^2-7=-6-3n^2 are n= 1/4 ,n=-1/4
Find the zeros of 13n^2-7=-6-3n^2
The zeros of 13n^2-7=-6-3n^2 are n= 1/4 ,n=-1/4