What are the solutions to the equation 6n^2+9n+1=0 ?

The solutions to the equation 6n^2+9n+1=0 are n=(-9+sqrt(57))/(12),n=(-9-sqrt(57))/(12)

Find the zeros of 6n^2+9n+1=0

The zeros of 6n^2+9n+1=0 are n=(-9+sqrt(57))/(12),n=(-9-sqrt(57))/(12)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 n^{2} + 9 n + 1 = 0

n = \frac{- 9 + 57}{12}, n = \frac{- 9 - 57}{12}

Decimal Notation

n = - 0.12084 \dots, n = - 1.37915 \dots

Solution steps

6 n^{2} + 9 n + 1 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 6 \cdot 1}{2 \cdot 6}

9^{2} - 4 \cdot 6 \cdot 1 = 57

n_{1, 2} = \frac{- 9 \pm 57}{2 \cdot 6}

Separate the solutions

n_{1} = \frac{- 9 + 57}{2 \cdot 6}, n_{2} = \frac{- 9 - 57}{2 \cdot 6}

n = \frac{- 9 + 57}{2 \cdot 6} : \frac{- 9 + 57}{12}

n = \frac{- 9 - 57}{2 \cdot 6} : \frac{- 9 - 57}{12}

The solutions to the quadratic equation are:

n = \frac{- 9 + 57}{12}, n = \frac{- 9 - 57}{12}

x^{2} + 15 x + 2 = 0

8 v^{2} - 6 = - 101

e^{2} x^{2} - 5 x - 7 = 1

x^{2} + 25 = 12 x

x^{2} - 18 x + 52 = 8

What are the solutions to the equation 6n^2+9n+1=0 ?
The solutions to the equation 6n^2+9n+1=0 are n=(-9+sqrt(57))/(12),n=(-9-sqrt(57))/(12)
Find the zeros of 6n^2+9n+1=0
The zeros of 6n^2+9n+1=0 are n=(-9+sqrt(57))/(12),n=(-9-sqrt(57))/(12)