What are the solutions to the equation x^2-18x+52=8 ?

The solutions to the equation x^2-18x+52=8 are x=9+sqrt(37),x=9-sqrt(37)

Find the zeros of x^2-18x+52=8

The zeros of x^2-18x+52=8 are x=9+sqrt(37),x=9-sqrt(37)

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x^{2} - 18 x + 52 = 8

x = 9 + 37, x = 9 - 37

Solution steps

x^{2} - 18 x + 52 = 8

Move

8

to the left side

x^{2} - 18 x + 44 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 44}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 44 = 237

x_{1, 2} = \frac{- ( - 18 ) \pm 2 37}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 2 37}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 2 37}{2 \cdot 1}

x = \frac{- ( - 18 ) + 2 37}{2 \cdot 1} : 9 + 37

x = \frac{- ( - 18 ) - 2 37}{2 \cdot 1} : 9 - 37

The solutions to the quadratic equation are:

x = 9 + 37, x = 9 - 37

s^{2} - 10 s + 21 = 0

15 a^{2} + a = 2

C = - 5 t^{2} + 750

- 12 x^{2} + 4 x = 0

(x - 9) (4 x - 8) = 0

What are the solutions to the equation x^2-18x+52=8 ?
The solutions to the equation x^2-18x+52=8 are x=9+sqrt(37),x=9-sqrt(37)
Find the zeros of x^2-18x+52=8
The zeros of x^2-18x+52=8 are x=9+sqrt(37),x=9-sqrt(37)