What are the solutions to the equation 15a^2+a=2 ?

The solutions to the equation 15a^2+a=2 are a= 1/3 ,a=-2/5

Find the zeros of 15a^2+a=2

The zeros of 15a^2+a=2 are a= 1/3 ,a=-2/5

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15 a^{2} + a = 2

a = \frac{1}{3}, a = - \frac{2}{5}

Decimal Notation

a = 0.33333 \dots, a = - 0.4

Solution steps

15 a^{2} + a = 2

Move

2

to the left side

15 a^{2} + a - 2 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 15 ( - 2 )}{2 \cdot 15}

1^{2} - 4 \cdot 15 (- 2) = 11

a_{1, 2} = \frac{- 1 \pm 11}{2 \cdot 15}

Separate the solutions

a_{1} = \frac{- 1 + 11}{2 \cdot 15}, a_{2} = \frac{- 1 - 11}{2 \cdot 15}

a = \frac{- 1 + 11}{2 \cdot 15} : \frac{1}{3}

a = \frac{- 1 - 11}{2 \cdot 15} : - \frac{2}{5}

The solutions to the quadratic equation are:

a = \frac{1}{3}, a = - \frac{2}{5}

C = - 5 t^{2} + 750

- 12 x^{2} + 4 x = 0

(x - 9) (4 x - 8) = 0

3 x^{2} - 3 x - 126 = 0

h^{2} + 6 h + 9 = 0

What are the solutions to the equation 15a^2+a=2 ?
The solutions to the equation 15a^2+a=2 are a= 1/3 ,a=-2/5
Find the zeros of 15a^2+a=2
The zeros of 15a^2+a=2 are a= 1/3 ,a=-2/5