What are the solutions to the equation -x^2-6x+7=0 ?

The solutions to the equation -x^2-6x+7=0 are x=-7,x=1

Find the zeros of -x^2-6x+7=0

The zeros of -x^2-6x+7=0 are x=-7,x=1

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- x^{2} - 6 x + 7 = 0

x = - 7, x = 1

Solution steps

- x^{2} - 6 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 1 ) \cdot 7}{2 ( - 1 )}

(- 6)^{2} - 4 (- 1) \cdot 7 = 8

x_{1, 2} = \frac{- ( - 6 ) \pm 8}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 8}{2 ( - 1 )}, x_{2} = \frac{- ( - 6 ) - 8}{2 ( - 1 )}

x = \frac{- ( - 6 ) + 8}{2 ( - 1 )} : - 7

x = \frac{- ( - 6 ) - 8}{2 ( - 1 )} : 1

The solutions to the quadratic equation are:

x = - 7, x = 1

7 x^{2} - 3 x + 5 = 0

8 x^{2} - 17 x + 2 = 0

(x - 1) (x + 7) = 0

- 2 x^{2} + 20 x - 24 = 0

4 + 7 x - 15 x^{2} = 0

What are the solutions to the equation -x^2-6x+7=0 ?
The solutions to the equation -x^2-6x+7=0 are x=-7,x=1
Find the zeros of -x^2-6x+7=0
The zeros of -x^2-6x+7=0 are x=-7,x=1