What are the solutions to the equation -2x^2+20x-24=0 ?

The solutions to the equation -2x^2+20x-24=0 are x=5-sqrt(13),x=5+sqrt(13)

Find the zeros of -2x^2+20x-24=0

The zeros of -2x^2+20x-24=0 are x=5-sqrt(13),x=5+sqrt(13)

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- 2 x^{2} + 20 x - 24 = 0

x = 5 - 13, x = 5 + 13

Solution steps

- 2 x^{2} + 20 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 ( - 2 ) ( - 24 )}{2 ( - 2 )}

2 0^{2} - 4 (- 2) (- 24) = 413

x_{1, 2} = \frac{- 20 \pm 4 13}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 20 + 4 13}{2 ( - 2 )}, x_{2} = \frac{- 20 - 4 13}{2 ( - 2 )}

x = \frac{- 20 + 4 13}{2 ( - 2 )} : 5 - 13

x = \frac{- 20 - 4 13}{2 ( - 2 )} : 5 + 13

The solutions to the quadratic equation are:

x = 5 - 13, x = 5 + 13

4 + 7 x - 15 x^{2} = 0

(x - 18)^{2} = 1

- x^{2} (2) - 4 + 4 (2) - 2 x = 0

r^{2} + 49 r = 0

- 3 x^{2} + 7 = 0

What are the solutions to the equation -2x^2+20x-24=0 ?
The solutions to the equation -2x^2+20x-24=0 are x=5-sqrt(13),x=5+sqrt(13)
Find the zeros of -2x^2+20x-24=0
The zeros of -2x^2+20x-24=0 are x=5-sqrt(13),x=5+sqrt(13)