What are the solutions to the equation factor 6x^2+7x=3 ?

The solutions to the equation factor 6x^2+7x=3 are x= 1/3 ,x=-3/2

Find the zeros of factor 6x^2+7x=3

The zeros of factor 6x^2+7x=3 are x= 1/3 ,x=-3/2

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6 x^{2} + 7 x = 3

x = \frac{1}{3}, x = - \frac{3}{2}

Solution steps

6 x^{2} + 7 x = 3

Move

3

to the left side

6 x^{2} + 7 x - 3 = 0

Factor

6 x^{2} + 7 x - 3 : (3 x - 1) (2 x + 3)

(3 x - 1) (2 x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 1 = 0 or 2 x + 3 = 0

Solve

3 x - 1 = 0 : x = \frac{1}{3}

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - \frac{3}{2}

x^{2} = 16

3 p^{2} - 5 p + 2 = 0

y^{2} - 10 y + 21 = 0

x = x^{2} + 2 x - 8

7 x^{2} - 3 x + 2 = 0

What are the solutions to the equation factor 6x^2+7x=3 ?
The solutions to the equation factor 6x^2+7x=3 are x= 1/3 ,x=-3/2
Find the zeros of factor 6x^2+7x=3
The zeros of factor 6x^2+7x=3 are x= 1/3 ,x=-3/2