What are the solutions to the equation y^2-10y+21=0 ?

The solutions to the equation y^2-10y+21=0 are y=7,y=3

Find the zeros of y^2-10y+21=0

The zeros of y^2-10y+21=0 are y=7,y=3

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y^{2} - 10 y + 21 = 0

y = 7, y = 3

Solution steps

y^{2} - 10 y + 21 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 21 = 4

y_{1, 2} = \frac{- ( - 10 ) \pm 4}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 10 ) + 4}{2 \cdot 1}, y_{2} = \frac{- ( - 10 ) - 4}{2 \cdot 1}

y = \frac{- ( - 10 ) + 4}{2 \cdot 1} : 7

y = \frac{- ( - 10 ) - 4}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

y = 7, y = 3

x = x^{2} + 2 x - 8

7 x^{2} - 3 x + 2 = 0

y^{2} - 10 y + 20 = 0

x, x^{2} + 2 x y + 3 y^{2} = 15

x, x^{2} + y^{2} + 4 y = - 4

What are the solutions to the equation y^2-10y+21=0 ?
The solutions to the equation y^2-10y+21=0 are y=7,y=3
Find the zeros of y^2-10y+21=0
The zeros of y^2-10y+21=0 are y=7,y=3