What are the solutions to the equation s(s-1)=2 ?

The solutions to the equation s(s-1)=2 are s=2,s=-1

Find the zeros of s(s-1)=2

The zeros of s(s-1)=2 are s=2,s=-1

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s (s - 1) = 2

s = 2, s = - 1

Solution steps

s (s - 1) = 2

Expand

s (s - 1) : s^{2} - s

s^{2} - s = 2

Move

2

to the left side

s^{2} - s - 2 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 2) = 3

s_{1, 2} = \frac{- ( - 1 ) \pm 3}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 1 ) + 3}{2 \cdot 1}, s_{2} = \frac{- ( - 1 ) - 3}{2 \cdot 1}

s = \frac{- ( - 1 ) + 3}{2 \cdot 1} : 2

s = \frac{- ( - 1 ) - 3}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

s = 2, s = - 1

x, x y = x^{2} + 4

x, x y = x^{2} + 2

\frac{2 ^{2}}{25} + \frac{y ^{2}}{9} = 1

g^{2} - 13 g - 48 = 0

x^{2} + 2.2 x + 1.21 = 0

What are the solutions to the equation s(s-1)=2 ?
The solutions to the equation s(s-1)=2 are s=2,s=-1
Find the zeros of s(s-1)=2
The zeros of s(s-1)=2 are s=2,s=-1