What are the solutions to the equation x^2+2.2x+1.21=0 ?

The solutions to the equation x^2+2.2x+1.21=0 are x=-11/10

Find the zeros of x^2+2.2x+1.21=0

The zeros of x^2+2.2x+1.21=0 are x=-11/10

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x^{2} + 2.2 x + 1.21 = 0

x = - \frac{11}{10}

Decimal Notation

x = - 1.1

Solution steps

x^{2} + 2.2 x + 1.21 = 0

Multiply both sides by

100

100 x^{2} + 220 x + 121 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 220 \pm 22 0 ^{2} - 4 \cdot 100 \cdot 121}{2 \cdot 100}

22 0^{2} - 4 \cdot 100 \cdot 121 = 0

x_{1, 2} = \frac{- 220 \pm 0}{2 \cdot 100}

x = \frac{- 220}{2 \cdot 100}

\frac{- 220}{2 \cdot 100} = - \frac{11}{10}

x = - \frac{11}{10}

The solution to the quadratic equation is:

x = - \frac{11}{10}

2 0^{2} = 1 0^{2} + x^{2}

85.183 x^{2} - 174.9 x + 93.362 = 34

x^{2} - \frac{2}{3} x - \frac{1}{3} = 0

(7 + 1) (x^{2} + 2 x) = (7 + 3) (3 x + 5)

y, f = 101 + ln (e^{2 x} + z^{3}) + x e^{z} - y^{2} z

What are the solutions to the equation x^2+2.2x+1.21=0 ?
The solutions to the equation x^2+2.2x+1.21=0 are x=-11/10
Find the zeros of x^2+2.2x+1.21=0
The zeros of x^2+2.2x+1.21=0 are x=-11/10