What are the solutions to the equation 20^2=10^2+x^2 ?

The solutions to the equation 20^2=10^2+x^2 are x=10sqrt(3),x=-10sqrt(3)

Find the zeros of 20^2=10^2+x^2

The zeros of 20^2=10^2+x^2 are x=10sqrt(3),x=-10sqrt(3)

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2 0^{2} = 1 0^{2} + x^{2}

x = 103, x = - 103

Solution steps

2 0^{2} = 1 0^{2} + x^{2}

Switch sides

1 0^{2} + x^{2} = 2 0^{2}

Move

1 0^{2}

to the right side

x^{2} = 300

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 300, x = - 300

300 = 103

- 300 = - 103

x = 103, x = - 103

85.183 x^{2} - 174.9 x + 93.362 = 34

x^{2} - \frac{2}{3} x - \frac{1}{3} = 0

(7 + 1) (x^{2} + 2 x) = (7 + 3) (3 x + 5)

y, f = 101 + ln (e^{2 x} + z^{3}) + x e^{z} - y^{2} z

x, x^{2} + 4 y^{2} + 4 x y + 12 = 0

What are the solutions to the equation 20^2=10^2+x^2 ?
The solutions to the equation 20^2=10^2+x^2 are x=10sqrt(3),x=-10sqrt(3)
Find the zeros of 20^2=10^2+x^2
The zeros of 20^2=10^2+x^2 are x=10sqrt(3),x=-10sqrt(3)