What are the solutions to the equation -3x^2+2x-5=0 ?

The solutions to the equation -3x^2+2x-5=0 are x= 1/3-i(sqrt(14))/3 ,x= 1/3+i(sqrt(14))/3

Find the zeros of -3x^2+2x-5=0

The zeros of -3x^2+2x-5=0 are x= 1/3-i(sqrt(14))/3 ,x= 1/3+i(sqrt(14))/3

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- 3 x^{2} + 2 x - 5 = 0

x = \frac{1}{3} - i \frac{14}{3}, x = \frac{1}{3} + i \frac{14}{3}

Solution steps

- 3 x^{2} + 2 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 3 ) ( - 5 )}{2 ( - 3 )}

Simplify

2^{2} - 4 (- 3) (- 5) : 214 i

x_{1, 2} = \frac{- 2 \pm 2 14 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 14 i}{2 ( - 3 )}, x_{2} = \frac{- 2 - 2 14 i}{2 ( - 3 )}

x = \frac{- 2 + 2 14 i}{2 ( - 3 )} : \frac{1}{3} - i \frac{14}{3}

x = \frac{- 2 - 2 14 i}{2 ( - 3 )} : \frac{1}{3} + i \frac{14}{3}

The solutions to the quadratic equation are:

x = \frac{1}{3} - i \frac{14}{3}, x = \frac{1}{3} + i \frac{14}{3}

5 X^{2} - 500 = 0

3 x^{2} + 32 x = 11

\frac{1}{2} x^{2} + x + 4 = 0

4 x^{2} = 8 x - 1

- 3 = \frac{1 2 ^{2}}{20} - \frac{10}{2 \cdot 1 2 ^{2}} \cdot x^{2}

What are the solutions to the equation -3x^2+2x-5=0 ?
The solutions to the equation -3x^2+2x-5=0 are x= 1/3-i(sqrt(14))/3 ,x= 1/3+i(sqrt(14))/3
Find the zeros of -3x^2+2x-5=0
The zeros of -3x^2+2x-5=0 are x= 1/3-i(sqrt(14))/3 ,x= 1/3+i(sqrt(14))/3