What are the solutions to the equation 3x^2+32x=11 ?

The solutions to the equation 3x^2+32x=11 are x= 1/3 ,x=-11

Find the zeros of 3x^2+32x=11

The zeros of 3x^2+32x=11 are x= 1/3 ,x=-11

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3 x^{2} + 32 x = 11

x = \frac{1}{3}, x = - 11

Solution steps

3 x^{2} + 32 x = 11

Move

11

to the left side

3 x^{2} + 32 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 \cdot 3 ( - 11 )}{2 \cdot 3}

3 2^{2} - 4 \cdot 3 (- 11) = 34

x_{1, 2} = \frac{- 32 \pm 34}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 32 + 34}{2 \cdot 3}, x_{2} = \frac{- 32 - 34}{2 \cdot 3}

x = \frac{- 32 + 34}{2 \cdot 3} : \frac{1}{3}

x = \frac{- 32 - 34}{2 \cdot 3} : - 11

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 11

\frac{1}{2} x^{2} + x + 4 = 0

4 x^{2} = 8 x - 1

- 3 = \frac{1 2 ^{2}}{20} - \frac{10}{2 \cdot 1 2 ^{2}} \cdot x^{2}

- 5 x^{2} - 5 x + 6 = 0

4 1^{2} = x^{2} + 4 0^{2}

What are the solutions to the equation 3x^2+32x=11 ?
The solutions to the equation 3x^2+32x=11 are x= 1/3 ,x=-11
Find the zeros of 3x^2+32x=11
The zeros of 3x^2+32x=11 are x= 1/3 ,x=-11