What are the solutions to the equation 41^2=x^2+40^2 ?

The solutions to the equation 41^2=x^2+40^2 are x=9,x=-9

Find the zeros of 41^2=x^2+40^2

The zeros of 41^2=x^2+40^2 are x=9,x=-9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 1^{2} = x^{2} + 4 0^{2}

x = 9, x = - 9

Solution steps

4 1^{2} = x^{2} + 4 0^{2}

Switch sides

x^{2} + 4 0^{2} = 4 1^{2}

Move

4 0^{2}

to the right side

x^{2} = 81

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 81, x = - 81

81 = 9

- 81 = - 9

x = 9, x = - 9

x^{2} - x = - \frac{1}{4}

x^{2} - 9 x + 19 = x - 5 x - 5

r^{2} = 4 r

x^{2} - 6 x = - 25

x^{2} = - 7 x + 6

What are the solutions to the equation 41^2=x^2+40^2 ?
The solutions to the equation 41^2=x^2+40^2 are x=9,x=-9
Find the zeros of 41^2=x^2+40^2
The zeros of 41^2=x^2+40^2 are x=9,x=-9