What are the solutions to the equation x^2=-7x+6 ?

The solutions to the equation x^2=-7x+6 are x=(-7+sqrt(73))/2 ,x=(-7-sqrt(73))/2

Find the zeros of x^2=-7x+6

The zeros of x^2=-7x+6 are x=(-7+sqrt(73))/2 ,x=(-7-sqrt(73))/2

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x^{2} = - 7 x + 6

x = \frac{- 7 + 73}{2}, x = \frac{- 7 - 73}{2}

Solution steps

x^{2} = - 7 x + 6

Move

6

to the left side

x^{2} - 6 = - 7 x

Move

7 x

to the left side

x^{2} - 6 + 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 7 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 6) = 73

x_{1, 2} = \frac{- 7 \pm 73}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 73}{2 \cdot 1}, x_{2} = \frac{- 7 - 73}{2 \cdot 1}

x = \frac{- 7 + 73}{2 \cdot 1} : \frac{- 7 + 73}{2}

x = \frac{- 7 - 73}{2 \cdot 1} : \frac{- 7 - 73}{2}

The solutions to the quadratic equation are:

x = \frac{- 7 + 73}{2}, x = \frac{- 7 - 73}{2}

x^{2} - 40 = - 16

x, 4 x^{2} + 9 y^{2} - 10 x - 54 y + 145 = 0

x, 0 = x^{2} - y^{2}

x^{2} + 15 x - 34 = 0

- 3 x^{2} + x + 6 = 0

What are the solutions to the equation x^2=-7x+6 ?
The solutions to the equation x^2=-7x+6 are x=(-7+sqrt(73))/2 ,x=(-7-sqrt(73))/2
Find the zeros of x^2=-7x+6
The zeros of x^2=-7x+6 are x=(-7+sqrt(73))/2 ,x=(-7-sqrt(73))/2