What are the solutions to the equation 4x^2+5=12 ?

The solutions to the equation 4x^2+5=12 are x=(sqrt(7))/2 ,x=-(sqrt(7))/2

Find the zeros of 4x^2+5=12

The zeros of 4x^2+5=12 are x=(sqrt(7))/2 ,x=-(sqrt(7))/2

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4 x^{2} + 5 = 12

x = \frac{7}{2}, x = - \frac{7}{2}

Solution steps

4 x^{2} + 5 = 12

Move

5

to the right side

4 x^{2} = 7

Divide both sides by

4

x^{2} = \frac{7}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{7}{4}, x = - \frac{7}{4}

\frac{7}{4} = \frac{7}{2}

- \frac{7}{4} = - \frac{7}{2}

x = \frac{7}{2}, x = - \frac{7}{2}

\frac{1}{8} x^{2} + \frac{5}{4} x + \frac{1}{3} = 0

4 x^{2} + 5 = - 7

2 x^{2} + 8 x - 384 = 0

x^{2} - 5 x + 2

14 x^{2} - 35 x = 0

What are the solutions to the equation 4x^2+5=12 ?
The solutions to the equation 4x^2+5=12 are x=(sqrt(7))/2 ,x=-(sqrt(7))/2
Find the zeros of 4x^2+5=12
The zeros of 4x^2+5=12 are x=(sqrt(7))/2 ,x=-(sqrt(7))/2