What are the solutions to the equation 2x^2+8x-384=0 ?

The solutions to the equation 2x^2+8x-384=0 are x=12,x=-16

Find the zeros of 2x^2+8x-384=0

The zeros of 2x^2+8x-384=0 are x=12,x=-16

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2 x^{2} + 8 x - 384 = 0

x = 12, x = - 16

Solution steps

2 x^{2} + 8 x - 384 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 ( - 384 )}{2 \cdot 2}

8^{2} - 4 \cdot 2 (- 384) = 56

x_{1, 2} = \frac{- 8 \pm 56}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 8 + 56}{2 \cdot 2}, x_{2} = \frac{- 8 - 56}{2 \cdot 2}

x = \frac{- 8 + 56}{2 \cdot 2} : 12

x = \frac{- 8 - 56}{2 \cdot 2} : - 16

The solutions to the quadratic equation are:

x = 12, x = - 16

x^{2} - 5 x + 2

14 x^{2} - 35 x = 0

n^{2} - 2 n - 28 = 0

(x - 3) (x - 4) = 12

4 x^{2} - 20 x + 20 = 0

What are the solutions to the equation 2x^2+8x-384=0 ?
The solutions to the equation 2x^2+8x-384=0 are x=12,x=-16
Find the zeros of 2x^2+8x-384=0
The zeros of 2x^2+8x-384=0 are x=12,x=-16