What are the solutions to the equation x^2+21x+104=0 ?

The solutions to the equation x^2+21x+104=0 are x=-8,x=-13

Find the zeros of x^2+21x+104=0

The zeros of x^2+21x+104=0 are x=-8,x=-13

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x^{2} + 21 x + 104 = 0

x = - 8, x = - 13

Solution steps

x^{2} + 21 x + 104 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 1 \cdot 104}{2 \cdot 1}

2 1^{2} - 4 \cdot 1 \cdot 104 = 5

x_{1, 2} = \frac{- 21 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 21 + 5}{2 \cdot 1}, x_{2} = \frac{- 21 - 5}{2 \cdot 1}

x = \frac{- 21 + 5}{2 \cdot 1} : - 8

x = \frac{- 21 - 5}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

x = - 8, x = - 13

x^{2} - 10 + 21 = 0

x^{2} - 4 x + 49 = 0

x^{(2)} + x^{(2)} + 2 x + 1 = x^{(2)} + 4 x + 4 + 60

x, 3 x^{2} - x y + 4 y^{2} - 2 x + 1 = 0

- (- 1) y - 1 = - (- 1) - y^{2}

What are the solutions to the equation x^2+21x+104=0 ?
The solutions to the equation x^2+21x+104=0 are x=-8,x=-13
Find the zeros of x^2+21x+104=0
The zeros of x^2+21x+104=0 are x=-8,x=-13