What are the solutions to the equation x^2-4x+49=0 ?

The solutions to the equation x^2-4x+49=0 are x=2+3sqrt(5)i,x=2-3sqrt(5)i

Find the zeros of x^2-4x+49=0

The zeros of x^2-4x+49=0 are x=2+3sqrt(5)i,x=2-3sqrt(5)i

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x^{2} - 4 x + 49 = 0

x = 2 + 35 i, x = 2 - 35 i

Solution steps

x^{2} - 4 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 49}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 49 : 65 i

x_{1, 2} = \frac{- ( - 4 ) \pm 6 5 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 6 5 i}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 6 5 i}{2 \cdot 1}

x = \frac{- ( - 4 ) + 6 5 i}{2 \cdot 1} : 2 + 35 i

x = \frac{- ( - 4 ) - 6 5 i}{2 \cdot 1} : 2 - 35 i

The solutions to the quadratic equation are:

x = 2 + 35 i, x = 2 - 35 i

x^{(2)} + x^{(2)} + 2 x + 1 = x^{(2)} + 4 x + 4 + 60

x, 3 x^{2} - x y + 4 y^{2} - 2 x + 1 = 0

- (- 1) y - 1 = - (- 1) - y^{2}

x^{2} + 7 x + 20 = 0

5 (2 x + 8)^{2} = - 80

What are the solutions to the equation x^2-4x+49=0 ?
The solutions to the equation x^2-4x+49=0 are x=2+3sqrt(5)i,x=2-3sqrt(5)i
Find the zeros of x^2-4x+49=0
The zeros of x^2-4x+49=0 are x=2+3sqrt(5)i,x=2-3sqrt(5)i