What are the solutions to the equation 5(2x+8)^2=-80 ?

The solutions to the equation 5(2x+8)^2=-80 are x=-4+2i,x=-4-2i

Find the zeros of 5(2x+8)^2=-80

The zeros of 5(2x+8)^2=-80 are x=-4+2i,x=-4-2i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 (2 x + 8)^{2} = - 80

x = - 4 + 2 i, x = - 4 - 2 i

Solution steps

5 (2 x + 8)^{2} = - 80

Divide both sides by

5

(2 x + 8)^{2} = - 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 8 = - 16 : x = - 4 + 2 i

Solve

2 x + 8 = - - 16 : x = - 4 - 2 i

The solutions to the quadratic equation are:

x = - 4 + 2 i, x = - 4 - 2 i

x^{2} - 32 x - 8 = 0

- x^{2} + 5 x - 3 = 0

x + 10 x^{2} - 12 x = x^{2} + 2 x

x^{2} - \frac{9}{2} x - \frac{24}{5} = 0

x, x^{2} + y^{2} - 4 x + 12 y + 40 = 0

What are the solutions to the equation 5(2x+8)^2=-80 ?
The solutions to the equation 5(2x+8)^2=-80 are x=-4+2i,x=-4-2i
Find the zeros of 5(2x+8)^2=-80
The zeros of 5(2x+8)^2=-80 are x=-4+2i,x=-4-2i