What are the solutions to the equation 4x^2-18x+18=0 ?

The solutions to the equation 4x^2-18x+18=0 are x=3,x= 3/2

Find the zeros of 4x^2-18x+18=0

The zeros of 4x^2-18x+18=0 are x=3,x= 3/2

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4 x^{2} - 18 x + 18 = 0

x = 3, x = \frac{3}{2}

Solution steps

4 x^{2} - 18 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 4 \cdot 18}{2 \cdot 4}

(- 18)^{2} - 4 \cdot 4 \cdot 18 = 6

x_{1, 2} = \frac{- ( - 18 ) \pm 6}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 6}{2 \cdot 4}, x_{2} = \frac{- ( - 18 ) - 6}{2 \cdot 4}

x = \frac{- ( - 18 ) + 6}{2 \cdot 4} : 3

x = \frac{- ( - 18 ) - 6}{2 \cdot 4} : \frac{3}{2}

The solutions to the quadratic equation are:

x = 3, x = \frac{3}{2}

6^{2} = x^{2} + 3^{2}

15 x^{2} - 15 = 0

x^{2} + 6 x - 7 = 0

(x^{2} + 4) \cdot 15 = (x - 3) (x - 5) \cdot 4

121 - a^{2} = 0

What are the solutions to the equation 4x^2-18x+18=0 ?
The solutions to the equation 4x^2-18x+18=0 are x=3,x= 3/2
Find the zeros of 4x^2-18x+18=0
The zeros of 4x^2-18x+18=0 are x=3,x= 3/2