What are the solutions to the equation 121-a^2=0 ?

The solutions to the equation 121-a^2=0 are a=11,a=-11

Find the zeros of 121-a^2=0

The zeros of 121-a^2=0 are a=11,a=-11

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121 - a^{2} = 0

a = 11, a = - 11

Solution steps

121 - a^{2} = 0

Move

121

to the right side

- a^{2} = - 121

Divide both sides by

- 1

a^{2} = 121

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = 121, a = - 121

121 = 11

- 121 = - 11

a = 11, a = - 11

4 - x^{2} = 4 - x

(x - 8)^{2} = - 16 x

m, f = (15 m \cdot 30 m) + 20 m^{2}

8 x - 65 + x^{2} = 0

0 = - 3 x^{2} + 30 x + 600

What are the solutions to the equation 121-a^2=0 ?
The solutions to the equation 121-a^2=0 are a=11,a=-11
Find the zeros of 121-a^2=0
The zeros of 121-a^2=0 are a=11,a=-11