What are the solutions to the equation x^2-5x=-9 ?

The solutions to the equation x^2-5x=-9 are x= 5/2+i(sqrt(11))/2 ,x= 5/2-i(sqrt(11))/2

Find the zeros of x^2-5x=-9

The zeros of x^2-5x=-9 are x= 5/2+i(sqrt(11))/2 ,x= 5/2-i(sqrt(11))/2

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x^{2} - 5 x = - 9

x = \frac{5}{2} + i \frac{11}{2}, x = \frac{5}{2} - i \frac{11}{2}

Solution steps

x^{2} - 5 x = - 9

Move

9

to the left side

x^{2} - 5 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

Simplify

(- 5)^{2} - 4 \cdot 1 \cdot 9 : 11 i

x_{1, 2} = \frac{- ( - 5 ) \pm 11 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 11 i}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 11 i}{2 \cdot 1}

x = \frac{- ( - 5 ) + 11 i}{2 \cdot 1} : \frac{5}{2} + i \frac{11}{2}

x = \frac{- ( - 5 ) - 11 i}{2 \cdot 1} : \frac{5}{2} - i \frac{11}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2} + i \frac{11}{2}, x = \frac{5}{2} - i \frac{11}{2}

x, x^{2} + y^{2} + 5 z^{2} + 2 x z + 4 yz - 4 = 0

\frac{x ^{2}}{10} - 4 = 12

3 c^{2} - 18 = 0

12 x^{2} - 11 x - 5 = 0

x^{2} - \frac{1}{2} x - \frac{3}{2} = 0

What are the solutions to the equation x^2-5x=-9 ?
The solutions to the equation x^2-5x=-9 are x= 5/2+i(sqrt(11))/2 ,x= 5/2-i(sqrt(11))/2
Find the zeros of x^2-5x=-9
The zeros of x^2-5x=-9 are x= 5/2+i(sqrt(11))/2 ,x= 5/2-i(sqrt(11))/2