What are the solutions to the equation (x^2)/(10)-4=12 ?

The solutions to the equation (x^2)/(10)-4=12 are x=4sqrt(10),x=-4sqrt(10)

Find the zeros of (x^2)/(10)-4=12

The zeros of (x^2)/(10)-4=12 are x=4sqrt(10),x=-4sqrt(10)

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\frac{x ^{2}}{10} - 4 = 12

x = 410, x = - 410

Solution steps

\frac{x ^{2}}{10} - 4 = 12

Move

4

to the right side

\frac{x ^{2}}{10} = 16

Multiply both sides by

10

x^{2} = 160

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 160, x = - 160

160 = 410

- 160 = - 410

x = 410, x = - 410

3 c^{2} - 18 = 0

12 x^{2} - 11 x - 5 = 0

x^{2} - \frac{1}{2} x - \frac{3}{2} = 0

\frac{16 ( x - 8 ) ^{2} + 25 ( \frac{9}{4} )}{400} = 1

4 x^{2} + 5 x + 20 = 0

What are the solutions to the equation (x^2)/(10)-4=12 ?
The solutions to the equation (x^2)/(10)-4=12 are x=4sqrt(10),x=-4sqrt(10)
Find the zeros of (x^2)/(10)-4=12
The zeros of (x^2)/(10)-4=12 are x=4sqrt(10),x=-4sqrt(10)