What are the solutions to the equation 4x^2+5x+20=0 ?

The solutions to the equation 4x^2+5x+20=0 are x=-5/8+i(sqrt(295))/8 ,x=-5/8-i(sqrt(295))/8

Find the zeros of 4x^2+5x+20=0

The zeros of 4x^2+5x+20=0 are x=-5/8+i(sqrt(295))/8 ,x=-5/8-i(sqrt(295))/8

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4 x^{2} + 5 x + 20 = 0

x = - \frac{5}{8} + i \frac{295}{8}, x = - \frac{5}{8} - i \frac{295}{8}

Solution steps

4 x^{2} + 5 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 4 \cdot 20}{2 \cdot 4}

Simplify

5^{2} - 4 \cdot 4 \cdot 20 : 295 i

x_{1, 2} = \frac{- 5 \pm 295 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 5 + 295 i}{2 \cdot 4}, x_{2} = \frac{- 5 - 295 i}{2 \cdot 4}

x = \frac{- 5 + 295 i}{2 \cdot 4} : - \frac{5}{8} + i \frac{295}{8}

x = \frac{- 5 - 295 i}{2 \cdot 4} : - \frac{5}{8} - i \frac{295}{8}

The solutions to the quadratic equation are:

x = - \frac{5}{8} + i \frac{295}{8}, x = - \frac{5}{8} - i \frac{295}{8}

12 x^{2} + 6 = 17 x

0 = - 4.9 x^{2} + 24.5 x + 9.5

y, y^{2} = 11 y - 28

1 0^{2} + x^{2} = 1 5^{2}

x, x^{2} = 2 y^{2}

What are the solutions to the equation 4x^2+5x+20=0 ?
The solutions to the equation 4x^2+5x+20=0 are x=-5/8+i(sqrt(295))/8 ,x=-5/8-i(sqrt(295))/8
Find the zeros of 4x^2+5x+20=0
The zeros of 4x^2+5x+20=0 are x=-5/8+i(sqrt(295))/8 ,x=-5/8-i(sqrt(295))/8