What are the solutions to the equation 2x^2+13=15 ?

The solutions to the equation 2x^2+13=15 are x=1,x=-1

Find the zeros of 2x^2+13=15

The zeros of 2x^2+13=15 are x=1,x=-1

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2 x^{2} + 13 = 15

x = 1, x = - 1

Solution steps

2 x^{2} + 13 = 15

Move

13

to the right side

2 x^{2} = 2

Divide both sides by

2

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

6 x^{2} - 37 x + 6 = 0

y^{2} + 7 y - 8 = 0

\frac{1}{9} = x^{2}

w^{2} + 4 w - 12 = 0

k^{2} + 3 k = 0

What are the solutions to the equation 2x^2+13=15 ?
The solutions to the equation 2x^2+13=15 are x=1,x=-1
Find the zeros of 2x^2+13=15
The zeros of 2x^2+13=15 are x=1,x=-1