What are the solutions to the equation x-6x^2=3x+x^2 ?

The solutions to the equation x-6x^2=3x+x^2 are x=-2/7 ,x=0

Find the zeros of x-6x^2=3x+x^2

The zeros of x-6x^2=3x+x^2 are x=-2/7 ,x=0

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x - 6 x^{2} = 3 x + x^{2}

x = - \frac{2}{7}, x = 0

Decimal Notation

x = - 0.28571 \dots, x = 0

Solution steps

x - 6 x^{2} = 3 x + x^{2}

Move

x^{2}

to the left side

x - 7 x^{2} = 3 x

Move

3 x

to the left side

- 7 x^{2} - 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 7 ) \cdot 0}{2 ( - 7 )}

(- 2)^{2} - 4 (- 7) \cdot 0 = 2

x_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2}{2 ( - 7 )}, x_{2} = \frac{- ( - 2 ) - 2}{2 ( - 7 )}

x = \frac{- ( - 2 ) + 2}{2 ( - 7 )} : - \frac{2}{7}

x = \frac{- ( - 2 ) - 2}{2 ( - 7 )} : 0

The solutions to the quadratic equation are:

x = - \frac{2}{7}, x = 0

x, x^{2} + 4 y^{2} = (x y - 14)^{2}

t^{2} - 18 = 0

b, a^{3} = 3 a b^{2} + 3 + 1.5 2

12 x^{2} - 84 x + 108 = 0

- x^{2} + 2 x = 0

What are the solutions to the equation x-6x^2=3x+x^2 ?
The solutions to the equation x-6x^2=3x+x^2 are x=-2/7 ,x=0
Find the zeros of x-6x^2=3x+x^2
The zeros of x-6x^2=3x+x^2 are x=-2/7 ,x=0