What are the solutions to the equation 12x^2-84x+108=0 ?

The solutions to the equation 12x^2-84x+108=0 are x=(7+sqrt(13))/2 ,x=(7-sqrt(13))/2

Find the zeros of 12x^2-84x+108=0

The zeros of 12x^2-84x+108=0 are x=(7+sqrt(13))/2 ,x=(7-sqrt(13))/2

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12 x^{2} - 84 x + 108 = 0

x = \frac{7 + 13}{2}, x = \frac{7 - 13}{2}

Solution steps

12 x^{2} - 84 x + 108 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 84 ) \pm ( - 84 ) ^{2} - 4 \cdot 12 \cdot 108}{2 \cdot 12}

(- 84)^{2} - 4 \cdot 12 \cdot 108 = 1213

x_{1, 2} = \frac{- ( - 84 ) \pm 12 13}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 84 ) + 12 13}{2 \cdot 12}, x_{2} = \frac{- ( - 84 ) - 12 13}{2 \cdot 12}

x = \frac{- ( - 84 ) + 12 13}{2 \cdot 12} : \frac{7 + 13}{2}

x = \frac{- ( - 84 ) - 12 13}{2 \cdot 12} : \frac{7 - 13}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 13}{2}, x = \frac{7 - 13}{2}

- x^{2} + 2 x = 0

x, x^{2} + y^{2} + x y = 0

s (s - 3) = 0

3 x^{2} - 46 x + 120 = 0

20 x^{2} + 5 x = 0

What are the solutions to the equation 12x^2-84x+108=0 ?
The solutions to the equation 12x^2-84x+108=0 are x=(7+sqrt(13))/2 ,x=(7-sqrt(13))/2
Find the zeros of 12x^2-84x+108=0
The zeros of 12x^2-84x+108=0 are x=(7+sqrt(13))/2 ,x=(7-sqrt(13))/2