What are the solutions to the equation 20x^2+5x=0 ?

The solutions to the equation 20x^2+5x=0 are x=0,x=-1/4

Find the zeros of 20x^2+5x=0

The zeros of 20x^2+5x=0 are x=0,x=-1/4

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20 x^{2} + 5 x = 0

x = 0, x = - \frac{1}{4}

Solution steps

20 x^{2} + 5 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 20 \cdot 0}{2 \cdot 20}

5^{2} - 4 \cdot 20 \cdot 0 = 5

x_{1, 2} = \frac{- 5 \pm 5}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- 5 + 5}{2 \cdot 20}, x_{2} = \frac{- 5 - 5}{2 \cdot 20}

x = \frac{- 5 + 5}{2 \cdot 20} : 0

x = \frac{- 5 - 5}{2 \cdot 20} : - \frac{1}{4}

The solutions to the quadratic equation are:

x = 0, x = - \frac{1}{4}

0 = 3 x^{2} + 2 x - 5

0 = 3 x^{2} + 2 x + 4

b^{2} - 7 b - 18 = 0

n^{2} + 5 n - 24 = 0

2 x^{2} + 2 x - 96 = 0

What are the solutions to the equation 20x^2+5x=0 ?
The solutions to the equation 20x^2+5x=0 are x=0,x=-1/4
Find the zeros of 20x^2+5x=0
The zeros of 20x^2+5x=0 are x=0,x=-1/4