What are the solutions to the equation 0=3x^2+2x+4 ?

The solutions to the equation 0=3x^2+2x+4 are x=-1/3+i(sqrt(11))/3 ,x=-1/3-i(sqrt(11))/3

Find the zeros of 0=3x^2+2x+4

The zeros of 0=3x^2+2x+4 are x=-1/3+i(sqrt(11))/3 ,x=-1/3-i(sqrt(11))/3

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0 = 3 x^{2} + 2 x + 4

x = - \frac{1}{3} + i \frac{11}{3}, x = - \frac{1}{3} - i \frac{11}{3}

Solution steps

0 = 3 x^{2} + 2 x + 4

Switch sides

3 x^{2} + 2 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

Simplify

2^{2} - 4 \cdot 3 \cdot 4 : 211 i

x_{1, 2} = \frac{- 2 \pm 2 11 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 2 11 i}{2 \cdot 3}, x_{2} = \frac{- 2 - 2 11 i}{2 \cdot 3}

x = \frac{- 2 + 2 11 i}{2 \cdot 3} : - \frac{1}{3} + i \frac{11}{3}

x = \frac{- 2 - 2 11 i}{2 \cdot 3} : - \frac{1}{3} - i \frac{11}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{3} + i \frac{11}{3}, x = - \frac{1}{3} - i \frac{11}{3}

b^{2} - 7 b - 18 = 0

n^{2} + 5 n - 24 = 0

2 x^{2} + 2 x - 96 = 0

0 = 3 x^{2} + 2 x - 8

r^{2} - 6 r = 0

What are the solutions to the equation 0=3x^2+2x+4 ?
The solutions to the equation 0=3x^2+2x+4 are x=-1/3+i(sqrt(11))/3 ,x=-1/3-i(sqrt(11))/3
Find the zeros of 0=3x^2+2x+4
The zeros of 0=3x^2+2x+4 are x=-1/3+i(sqrt(11))/3 ,x=-1/3-i(sqrt(11))/3